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Q(x)= -2x+1
r (x)=x²+2
Find the value of r r(q (2)).

Q(x)= -2x+1 r (x)=x²+2 Find the value of r r(q (2)).-example-1
User Gyim
by
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1 Answer

6 votes

Answer:

r(q(2)) = 11

Explanation:

given r(x) = x^2 + 2, and q(x) = -2x + 1.

Here is the equation to the composite function:

r(q(x)) = (-2x+1)^2 + 2 = 4x^2-4x+3 .

Then just substitute the input and solve:

r(q(2)) = 4(2)^2- 4(2) + 3 = 16 - 8 + 3 = 16 - 5 = 11

______________________________

Or if you don't like this, first find the answer to q(2) = -2(2) + 1 = -3

Then substitute this value into the second equation r(x).

r(x) → r(-3) = (-3)^2 + 2 = 9 + 2 = 11

User Pankijs
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