The line 3x + 2y = 6 can be graphed by rewriting it in slope-intercept form:
. Plotting the y-intercept (0, 3) and another point, the line can be drawn on the graph.
To graph the line 3x + 2y = 6 in standard form, we can rewrite it in slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.
First, solve for y:
![\[3x + 2y = 6\]\[2y = -3x + 6\]\[y = -(3)/(2)x + 3\]](https://img.qammunity.org/2021/formulas/mathematics/high-school/4itnfee9l9m6fwqcr3nbmjwwl9qqbnqe7q.png)
Now we can see that the slope m is
and the y-intercept b is 3.
Plot the y-intercept at (0, 3), and use the slope to find another point. For example, if you let x = 2, then
.
Plot these points and draw the line.