Question

A watch which looses a half a minute every hour was set to read the correct time at 0445hr on Monday. Determine in twelve hour system the time the watch will show on Friday at 1845hr the same week.

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Answer 1

The watch loses half a minute every hour, and from Monday at 0445hr to Friday at 1845hr is 110 hours. The watch will lose 55 minutes in total, so it will show 1750hr or 5:50 PM on Friday in the twelve-hour system.

Step-by-step explanation:

The question involves calculating the time deviation of a watch that loses half a minute every hour from the correct time. The watch was set to the correct time at 0445hr on Monday, and we need to determine what time it will show at 1845hr on Friday in the same week.

First, let's calculate the total time from Monday at 0445hr to Friday at 1845hr:

Adding these up gives a total of 24 + 72 + 14 = 110 hours.

Since the watch loses half a minute every hour, the total time lost in 110 hours is 110 x 0.5 minutes = 55 minutes.

Subtracting this loss from the actual time on Friday at 1845hr, we find:

Therefore, the watch will show 1750hr, or in the twelve-hour system, it will be 5:50 PM on Friday.

Answer 2

see below

Step-by-step explanation:

Using a 24 HOUR SYSTEM

The total time from Monday to Friday times given

= 24 x 4 + (18:45 - 4:45) = 96 + 14 = 110 hours

110 hours * 30/3600 = .91667 hours lost = 55 minutes lost

watch will show 18:45 - 55 minute = 17:50 ( 5:50 in 12-hour system)