Answer:
The correct option is C
Step-by-step explanation:
From the question we are told that
The speed of the ball in the horizontal direction is
![v = 40 m/s](https://img.qammunity.org/2021/formulas/physics/high-school/odkwoynokqmi5i9hjo442i1o3fvjyz411q.png)
The height from which the ball is thrown is s = 2 m
Generally from kinematic equation
![s = ut + (1)/(2) gt^2](https://img.qammunity.org/2021/formulas/physics/college/eom91dsrwutcwdpf43vlp8bbi8diy6vdnp.png)
Here u is the initial velocity of the ball and this zero given that the ball was at rest before it was thrown.
So
![2 = 0 * t + (1)/(2) 9.8t^2](https://img.qammunity.org/2021/formulas/physics/high-school/bbg1v1brittt5uaz58ddtsmu6a52kros9r.png)
=>
![t = 0.6889 \ s](https://img.qammunity.org/2021/formulas/physics/high-school/asdh4awfab1waxd3iasa7mxba7z8r9t9v6.png)
Generally the distance the ball will travel before touching the ground is
![d = v * t](https://img.qammunity.org/2021/formulas/physics/college/4czev5h2qyut6b18pam209gbrx1nt12804.png)
=>
![d = 40 * 0.6389](https://img.qammunity.org/2021/formulas/physics/high-school/xmbsy2gqrbnzec0zvpp3hoq02n6mb2u3f9.png)
=>
![d = 25.56 \ m](https://img.qammunity.org/2021/formulas/physics/high-school/6js8fc1h4v3pn8ygg9e04v2gobunlw0tbx.png)