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A student throws a ball horizontally at the rate of 40 m/s. If the height from which the ball is thrown is 2 m, how far will the ball travel before it touches the ground?

a-16.33m
b-19.54m
c-25.56m
d-28.29m

User KVISH
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1 Answer

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Answer:

The correct option is C

Step-by-step explanation:

From the question we are told that

The speed of the ball in the horizontal direction is
v = 40 m/s

The height from which the ball is thrown is s = 2 m

Generally from kinematic equation


s = ut + (1)/(2) gt^2

Here u is the initial velocity of the ball and this zero given that the ball was at rest before it was thrown.

So


2 = 0 * t + (1)/(2) 9.8t^2

=>
t = 0.6889 \ s

Generally the distance the ball will travel before touching the ground is


d = v * t

=>
d = 40 * 0.6389

=>
d = 25.56 \ m

User Marleni
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