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Question 3 If AD = 5x +3, DC=2x + 4,AB=15, and BC=12, find the value of AD.​

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Answer:

ad =4

Explanation:

User Edward Olamisan
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It is to be noted that where the above is given, the value of AD is 7 Option A.

AD/Sin ∠ABD = AB/Sin ∠ADB

DC/Sin ∠DBC = BC/ Sin ∠BDC
DC /Sin ∠ABD = BC/Sin(π-∠ADB)

2x + 4/Sin∠ABD = 12/Sin (π-∠ADB) = 12 / Sin ∠ADB
5x + 3/Sin ∠ABD = 15/Sin ∠ADB

2x + 4/ 5x + 3 = 12/15 = 4/5
20x + 12 = 10x + 20
10x = 8
x = 0.8

AD = 5x + 3
= 5 (0.8) + 3

= 4 + 3
= 7

Full Question:

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Question 3 If AD = 5x +3, DC=2x + 4,AB=15, and BC=12, find the value of AD.​-example-1
User Aater Suleman
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