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12 votes
Evaluate
4! - (11-2)!
8!

User Vliu
by
7.4k points

1 Answer

12 votes

Answer:

Explanation:

The expanded value of n! is (n) * (n - 1) * (n - 2) until we reach one.

Given:

4! - ((11-2)!) / 8!)

Rewrite:


\displaystyle 4! - ((11-2)!)/(8!)

Subtract:


\displaystyle 4! - (9!)/(8!)

Expand:


\displaystyle 4*3*2*1 - (9*8*7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1)

Cancel out values that equal one in the fraction:


\displaystyle 4*3*2*1 - (9)/(1)

Multiply:


\displaystyle 24 - (9)/(1)

Simplify:

24 - 9

Subtract:

15

User Ritu Gupta
by
7.3k points