Answer:
Explanation:
The standard form of equation of a line in slope-intercept form is expressed as:
y =mx+c
m is the slopw
c is intercept
Get the slope of the known line
since y = -2x+5
slope m = -2
Get the slope of unknown line
Since the unknown line is perpendicular to tis line, then
Mm = -1
M = -1/m
M = -1/-2
m = 1/2
Get the intercept of the unknown line:
Substitute the point (-6,12) and m = 1/2 into the equation y = mx+c
12 = 1/2(-6) + c
-12 = -3 + c
c = -12+3
c = -9
Get the equation of the unknown line:
Substitute m = 1/2 and c = -9 into the equation y = mx+c
y = 1/2x -9
2y = x - 18
2y-x = -18
Hence the equation in slope-intercept form of a line that passes through the point (-6, -12) and is perpendicular to y=-2x+5 is 2y-x = 18