The missing figure is attached down
Answer:
The coordinates of the vertices of Δ A'B'C' are A' (-3, 3), B' (-1, 1), C' (-2, 3) ⇒ A
Explanation:
If the point (x, y) reflected across the x-axis , then its image is (x, -y)
If the point (x, y) translated vertically up by k units then its image is (x, y + k)
Let us solve the question using the rules above
∵ The coordinates of Δ ABC are A (-3, 1), B (-1, 3), C = (-2, 1)
∵ Δ ABC reflected across the x-axis at first
→ By using the first rule above change the signs of y coordinates
∴ The image of A = (-3, -1)
∴ The image of B = (-1, -3)
∴ The image of C = (-2, -1)
∵ Then it translated 4 units up
→ Use the second rule above, where k = 4, add each y-coordinates by 4
∴ A' = (-3, -1 + 4)
∴ A' = (-3, 3)
∴ B' = (-1, -3 + 4)
∴ B' = (-1, 1)
∴ C' = (-2, -1 + 4)
∴ C' = (-2, 3)
The coordinates of the vertices of Δ A'B'C' are A' (-3, 3), B' (-1, 1), C' (-2, 3)