Question

2. A 60 kg crate is being lowered from a loading dock to the floor of a warehouse by a thick rope. The rope exerts a constant upward force of 500 N as it is descending to the floor. a) Draw a free-body diagram for the crate. b) Calculate the acceleration (if any) of the crate.​

Answer 1

Acceleration =8.33m/s^2

Step-by-step explanation:

Step one:

Kindly find attached a sketch of the free body diagram

Given data

mass m=60kg

Force F=500N

a=?

Step two:

From Newton's second law "An object’s acceleration equals the vector sum of the forces acting on it, divided by it mass".

mathematically

F=ma

Step three:

Substituting we have

500=60*a

a=500/60

a=8.33m/s^2