Answer:
The correct options are;
1) The data for store 1 show greater variability
2) The mean of the data for store 1 is greater than the mean of the data for store 2
Explanation:
The given information are;
Hours worked in a week
Store 1
16, 28, 36, 40, 78
Store 2
22, 27, 33, 36, 40
Using an online application, we have;
For store 1
The range is 78 - 16 = 62
Mean = 39.6
Standard deviation ≈ 20.88 (Higher variability)
Median = 36
Lower quartile = 22
Upper quartile = 59
Interquartile range = 59 - 22 = 37
For store 2
The range is 40 - 22 = 18
Mean = 31.6
Standard deviation ≈ 6.41 (Lower variability)
Median = 33
Lower quartile = 24.5
Upper quartile = 38
Interquartile range = 38 - 24.5 = 13.5