Question

What is the perimeter of the composite figure? Round to the nearest tenth

Answer 1

The perimeter of ABCDEF is 125.5 units.

The vertices of the composite figure are labeled A through F.

Thus, Perimeter of ABCDEF = AB+BC+CD+DE+EF+FA

AB= |-12-6| = 18 units

BC = |-12-3| = 15 units

CD= |6 - 15| = 9 units

DE = √(x2-x1)2+(y2-y1)²

= √(24-15)² + (18-3)²

= √9² +15² √81 +225

= √306

= 17.5units

EF = |-12 -24|= 36 units

FA= |-12-18| = 30 units

Thus, Perimeter of ABCDEF = 18 + 15 + 9 + 17.5 +36 + 30 = 125.5 units

Answer 2

125.5 units

Explanation:

The vertices of the composite figure has been named A to F.

*See attachment below.

Thus, Perimeter of ABCDEF =
`\overline{AB} + \overline{BC} + \overline{CD} + \overline{DE} + \overline{EF} + \overline{FA}`

`\overline{AB}` = |-12 - 6| = 18 units

`\overline{BC}` = |-12 - 3| = 15 units

`\overline{CD}` = |6 - 15| = 9 units

`\overline{DE} = √((x_2 - x_1)^2 + (y_2 - y_1)^2) = √((24 - 15)^2 + (18 - 3)^2) = √(9^2 + 15^2) = √(81 + 225) = √(306) = 17.5 units`

`\overline{EF}` = |-12 - 24| = 36 units

`\overline{FA}` = |-12 - 18| = 30 units

Thus, Perimeter of ABCDEF = 18 + 15 + 9 + 17.5 + 36 + 30 = 125.5 units