Answer:
The equation that models the path of the ball is y = 5·x - 0.05·x²
Explanation:
The given information are;
The distance the football landed from where it was kicked = 100 feet
The maximum height the football reached = 125 feet
The equation that models the path of the ball is that of the equation of parabola in vertex form, given as follows;
y = a·(x - h)² + k
Where;
(h, k) = The coordinate of the vertex (which is the coordinates of the highest point reached by the ball)
Therefore, taking the x-coordinate of the highest point reached by the ball as midpoint of the horizontal distance moved by the ball, we have;
The x-coordinate of the midpoint of the horizontal distance moved by the ball = (50, 0)
We have;
The coordinate of the highest point reached by the ball = (50, 125)
Therefore;
(h, k) = (50, 125)
Substituting the above values in the equation of the parabola gives;
y = a·(x - 50)² + 125
At x = 100, y = 0, which gives;
0 = a·(100 - 50)² + 125 = a·2500 + 125
0 = a·2500 + 125
a = -125/2500 = -0.05
Therefore, we have;
y = a·(x - h)² + k = y = -0.05 × (x - 50)² + 125 = -0.05·x² + 5·x - 125 + 125
y = -0.05·x² + 5·x - 125 + 125 = -0.05·x² + 5·x
y = -0.05·x² + 5·x
The equation that models the path of the ball is y = -0.05·x² + 5·x.