Question

Unit 3 Closing Activity

Your task is to package 36 cans of tennis balls for shipping. Each tennis ball can contain 3 tennis balls.
You must box them in two rows of 18 cans.

When you go to the box store to purchase a box, you notice that the boxes come in a variety of sizes. All dimensions are in multiples of 6” (ie. 6”, 12”, 18”, etc.). Assume the diameter of one tennis ball is 3 inches. Use 3.14 as the value of .

When talking to the shipping clerk, you find out that there is an extra charge for any extra space in the shipping box that is not taken up by the cans because they have to fill that space in with a filler. Since you are on a tight budget, you want to spend the least amount of money as possible to ship this box.

Your task:

Choose the size box that fits the cans for your shipment.

L= W= H=



2) Determine how much extra space there is in your box after you have put the cans in

Answer 1

1) L = 54", W = 6", H = 9"

2) Extra Space = 1389.96 in³

Explanation:

1)

LENGTH:

Since, there will be 18 balls along the length of box. Therefore,

Length = L = (18 balls)(Diameter of 1 ball) = (18)(3'')

L = 54"

WIDTH:

Since, there will be 2 rows of cans, and hence, 2 balls along the width of box. Therefore,

Width = W = (2 balls)(Diameter of 1 ball) = (2)(3'')

W = 6"

HEIGHT:

Since, each can can hold 3 balls along the height of box. Therefore,

Height = H = (3 balls)(Diameter of 1 ball) = (3)(3'')

H = 9"

2)

First we calculate the total volume of box:

Total Volume = L*W*H = (54")(6")(9") = 2916 in³

Now, we calculate volume of one ball:

Volume of 1 Ball = (4/3)π(d/2)³ = (4/3)π(3"/2)³ = 14.13 in³

Now, we calculate the total number of balls in box:

No. of Balls = (Balls along length)(Balls along width)(Balls along height)

No. of Balls = (18)(2)(3) = 108 balls

Now, we calculate the total volume of box occupied by balls:

Total Volume occupied by Balls = (No. of balls)(Volume of 1 Ball)

Total Volume occupied by Balls = (108)(14.13 in³)

Total Volume occupied by Balls = 1526.04 in³

Hence, the extra space will be:

Extra Space = Total Volume of Box - Total Volume Occupied by Balls

Extra Space = 2916 in³ - 1526.04 in³

Extra Space = 1389.96 in³