Question

A truck is traveling at an initial velocity

of +39m/s and it starts slowing down smoothly for 3.3s. It covers a distance of 45m while slowing down. What is the acceleration?​

Answer 1

Approximately
`-15.37m/s^2`

Step-by-step explanation:

The acceleration can be found using the formula:

`x_(f) = x_(i) + v_(i) (t)+(1)/(2) (a)(t^(2) )`

The work is as shown:

`45m = 0 + 39 m/s (3.3s)+(1)/(2) a(3.3s)^2`

`45m=128.7m + 5.445s^2 a`

`-83.7m=5.445s^2a`

`a = -15.37190083m/s^2`

a is about -15.37
`m/s^2`