Question

Anyone please help meಥ‿ಥ​

Answer 1

see explanation

Explanation:

the mean is calculated as

mean =
`(sum)/(count)`

the median is the middle value of a set of data. If there is no exact middle value then it is the average of the values on either side of the middle.

the mode is the value that occurs most often in the data set

A data set can have more than 1 mode

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(3)

(a)

mean =
`(74+73+75+76+71+69+70+76+76+86)/(10)` =
`(746)/(10)` = 74.6

(b)

Arrange the data in ascending order

69 70 71 73 74 75 76 76 76 86

↑ middle

median = (74 + 75) ÷ 2 = 149 ÷ 2 = 74.5

(c)

mode = 76

(4)

(a)

mean =
`(6+8+8+5+6+7+5+3+5)/(9)` =
`(53)/(9)` ≈ 5.9 ( to 1 dec. place )

(b)

3 5 5 5 6 6 7 8 8

↑ middle

median = 6

(c)

mode = 5

(5)

(a)

mean =
`(12+13+18+23+14+17+14+16+13+16+15+19+11+20+12)/(15)` =
`(233)/(15)` ≈ 15.5 ( to 1 dp )

(b)

11 12 12 13 13 14 14 15 16 16 17 18 19 20 23

↑ middle

median = 15

(c)

the mode is multimodal

modes are 12, 13, 14, 16

Answer 2

Mean: The sum of all data values divided by the total number of data values.

Median: The middle value when all data values are placed in order of size. If there is an even number of data values, the median is the mean of the middle two values.

Mode: The most frequently occurring data value.

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Question 3

`\textsf{Mean}=(69 + 70 + 71 + 73 + 74 + 75 + 76 + 76 + 76 + 86)/(10)=74.6`

Ordered data values: 69, 70, 71, 73, 74, 75, 76, 76, 76, 86

Median = (74 + 75) / 2 = 74.5

Mode = 76

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Question 4

`\textsf{Mean}=(3 + 5 + 5 + 5 + 6 + 6 + 7 + 8 + 8)/(9)=5.9\: \sf (nearest \:tenth)`

Ordered data values: 3, 5, 5, 5, 6, 6, 7, 8, 8

Median = 6

Mode = 5

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Question 5

`\begin{aligned}\textsf{Mean} & =(11 + 12 + 12 + 13 + 13 + 14 + 14 + 15 + 16 + 16 + 17 + 18 + 19 + 20 + 23)/(15)\\ & =15.5 \: \sf (nearest\:tenth)\end{aligned}`

Ordered data values: 11, 12, 12, 13, 13, 14, 14, 15, 16, 16, 17, 18, 19, 20, 23

Median = 15

Mode = 12, 13, 14, 16