Question

C. The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m/s. If the driver slams on her brakes and slows down at a rate of -8.2 m/s2, what is the stopping distance for the car in this situation

Answer 1

The stopping distance for the car when the driver slams on her brakes is 7.38 m.

Step-by-step explanation:

The distance traveled for the car after stopping can be found using the following equation:

`v_(f)^(2) = v_(0)^(2) + 2ad`

Where:

vf is the final speed = 0 (it stops)

v₀ is the initial speed = 11 m/s

a is the acceleration = -8.2 m/s²

d is the distance =?

When the driver slams on her brakes the distance traveled is:

`d = -(v_(0)^(2))/(2a) = -((11 m/s)^(2))/(2*(-8.2 m/s^(2))) = 7.38 m`

Therefore, the stopping distance for the car when the driver slams on her brakes is 7.38 m.

I hope it helps you!