Question

Type the correct answer in each box. Use numerals instead of words.

The zeros of the function f(x) = -(x+1)(x-3) ( x+ 2) are -1,3, and blank the y-intercept of the function is located at (0, blank)

Answer 1

see explanation

Explanation:

f(x) = - (x + 1)(x - 3)(x + 2)

to find the zeros let f(x) = 0 , that is

- (x + 1)(x - 3)(x + 2) = 0

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x - 3 = 0 ⇒ x = 3

x + 2 = 0 ⇒ x = - 2

the zeros are x = -1, 3 and x = - 2

to find the y- intercept let x = 0

f(0) = - (0 + 1)(0 - 3)(0 + 2) = - (1)(- 3)(2) = - (- 6) = 6

y- intercept is located at (0, 6 )