Sample problem is;
A child slides down a steep, snow covered hill with an acceleration of 2.82 m/s². Her initial speed is 0.0 m/s² and her final speed is 15.5 m/s travelling from top to bottom of the hill.
Answer:
t = 39.54 s
Explanation:
We are told that her acceleration is now -0.392 m/s²
Thus; a = -0.392 m/s²
From the sample problem, we have;. Initial velocity = 0 m/s
Final velocity = 15.5 m/s
However, in this question, we want to find the time from the bottom of the hill to her stopping point.
This means her initial velocity will now be; u = 15.5 m/s and final velocity since she will come to rest will be v = 0 m/s
To find the time it takes her to travel from the bottom of the hill to her stopping point, we will use Newton's equation of motion and so, we have;
v = u + at
making t the subject, we have;
t = (v - u)/a
t = (0 - 15.5)/(-0.392)
t = 39.54 s