Question

A 0.414 kg object is at rest at the origin of a coordinate system. A 2.08 N force in the positive x direction acts on the object for 1.57 s. What is the velocity at the end of this interval

Answer 1

The value is
`v = 7.89 \ m/s`

Step-by-step explanation:

From the question we are told that

The mass of the object is
`m = 0.414 \ kg`

The force is
`F = 2.08 \ N`

The time taken is
`t = 1.57 \ s`

Generally the force acting on the object according to Newton's second law is

`F = ( m (v -u ))/(t)`

=>
`v = (F * t)/(m) + u`

Here u is the initial velocity with value 0 m/s since the object was initially at rest

`v = (2.08 * .57)/(0.414 ) + 0`

`v = 7.89 \ m/s`