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Determine the required height h of the crest of the roller coaster to thebottom so that when it is essentially at rest at the crest of the hill it will reacha speed of 28 m/s when it comes to the bottom.

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Answer:

h = 40 m

Step-by-step explanation:

  • Assuming no friction present, total mechanical energy must be conserved, so the following expression stands:
  • ΔK + ΔU = 0 (1)
  • Now, if the car is at rest at the crest of the hill, the change in kinetic energy is just as follows:


\Delta K = (1)/(2) * m* v_(b) ^(2) (2)

where vb = speed at the bottom = 28 m/s

  • If we define the bottom as our zero reference level for the gravitational potential energy, we can write the following equation:


\Delta U = U_(f) - U_(i) = 0- m*g*h = -m*g*h (3)

  • From (1) we get:
  • ΔK = -ΔU
  • Replacing by (2) and (3), we get:


(1)/(2) * m* v^(2) = m*g*h

  • Simplifying and rearranging terms, we can solve for h (height required) as follows:


h = (v_(b) ^(2) )/(2*g) = ((28m/s)^(2))/(2*9.8m/s2) = 40 m

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