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How many moles of HCl needs to be added to a solution containing 0.10 mol of NH3 to make a buffer of pH 9.26

User Enkara
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1 Answer

5 votes

Answer:

The correct solution is "0.05 mol".

Step-by-step explanation:

According to the question,


NH_(3)(aq)+HCL(aq)\rightarrow NH_(4)^+Cl^-(aq)

0.10 x 0

(0.10-x) 0 x

Now,


pH=pKa+log([NH_(4)Cl])/([NH_(3)])


9.26=9.26+log((x)/(0.10-x) )


log((x)/(0.10-x))=0


(x)/(0.10-x)=1


2x=0.10


x=0.05 (moles of HCL needed)

User Ivaylo Toskov
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