Answer:
It moves inwards towards the center of the distribution
Step-by-step explanation:
It is given :
Number of degrees of freedom , df = 19
α = 0.05
α/2 = 0.05/2 = 0.025
Therefore,
![$t_(\alpha/2, df) = t_(0.025,19) = \pm 2.093$](https://img.qammunity.org/2021/formulas/engineering/college/iaroklrm6v4lze1vuzzhoamizy3loqw14y.png)
So critical value of t = ± 2.093
Therefore, the curve moves towards the center of the distribution.