Question

What is the maximum torque on a 213-turn square loop of wire 18.0 cm on a side that carries a 65.0-A current in a 1.60-T field

Answer 1

The maximum torque on the loop is 717.73 N.m

Step-by-step explanation:

Given;

number of turns, N = 213 turns

side of the square loop, L = 18 cm = 0.18 m

current in the loop, I = 65 A

magnetic field though the loop, B = 1.6 T

Area of the loop, A = L² = (0.18 )² = 0.0324 m²

The maximum torque on the loop is given by;

τ = NBIA

Substitute the given values and solve for maximum torque (τ);

τ = (213)(1.6)(65)(0.0324)

τ = 717.73 N.m

Therefore, the maximum torque on the loop is 717.73 N.m