Question

Part A What electron current is driven through a 2.3-mm-diameter iron wire by a 0.062 V/m electric field?

Answer 1

We know, Current is given by :

`I = (EA)/(\rho)`

Here,
`\rho` is resistivity and for iron.

`\rho=9.71* 10^(-8)\ \Omega\ m`

Putting
`\rho` in above equation, we get :

`I = (0.062* \pi* (2.3* 10^(-3))^2)/(4* 9.71* 10^(-8))`

`I=2.65\ A`

Therefore, the electron current is 2.65 A.

Hence, this is the required solution.