Answer:
The range of scores that can earn Jeremiah a B in the course is 80 - 100
Explanation:
Average = total scores/number of exams
For an average of 80, considering the final score has twice the weight of the previous exams;
Note: since the final score has twice the weight of previous exams, it is considered a double score and counted twice
Let the lowest final score for a B grade be y
80 = (69 + 78 + 81 + 92 + 2 * y)/6
80 * 6 = (320 + 2y)
2y = 480 - 320
y = 160/2
y = 80
Let the highest final score for a B grade be z
89 = (69 + 78 + 81 + 92 + 2 * z)/6
89 * 6 = (320 + 2z)
2z = 534 - 320
z = 214/2
z = 107
Since, the highest score in the exam cannot exceed 100,
Therefore, the range of scores that can earn Jeremiah a B in the course is 80 - 100