Answer:Current across 10ohm, I =0.59 A
Step-by-step explanation:
Total Resistance n parallel s given as
1/Rt = 1/R1 + 1/R2 + 1/R3
1/Rt = 1/4 + 1/6 + 1/10
1/Rt = 0.51666
Rt = 1/0.51666
Rt = 1.935 ohms
which is now connected In series with a ohm resstor
Rnet in series = R1+ R2
Rnet = 1.935 + 2.0 = 3.935 ohms
Since a voltage of 12 V s connected with the resistors in series, we have that the net current flowing across the 2ohm and 1.935ohm will be
Current, I = Voltage, V/ Resistance, R net
I= I2 / 3.935= 3.049 A
the Voltage across the 1.935 ohm resistance
V= 1R
3.049 X 1.935 = 5.899 Volts
remember that 1.935 ohm s the resultant resistance connected in parallel, therefore The voltage across the 1.935 ohm is same for the 10 ohm, 4ohm and 6ohm resistances
Therefore, the current passing through the 10ohm resistance will be
Current across 10ohm, I = V/R = 5.899/10 = 0.5899 Ampere ≈0.59 A