Answer:
Step-by-step explanation:
Since both loads at connected in parallel, the voltage across them will be the same.
The voltage across parallel connected loads are the same.
Let the loads be R1 and R2
Power = IV
I is the current
V is the voltage
P= V²/R
R = V²/P
Get the first load R1
R1 = V²/P1
R1 = 120²/40
R1 = 360ohms
Get the second load R2
R2 = V²/P2
R2 = 120²/75
R2 = 192ohms
Current in R1 will be;
P1 = I1²R1
I1² = P/R1
I1² = 40/360
I1² = 1/9
I1 = √1/9
I1 = 1/3
I = 0.33A
Current in R2(second load) will be;
P2 = I2²R2
I2² = P/R2
I2² = 75/192
I2² = 0.390625
I2 = √0.390625
I2 = 0.625A