Question

sound intensity varies inversely as the square of the distance from the sound source. if you are in a movie theater and you change your seat to one that is eight times as far from the speakers, how does the new sound intensity compare with that of your original seat

Answer 1

`(1)/(64)` as loud.

Step-by-step explanation:

The sound intensity varies inversely as the square of the distance from the sound source. Mathematically,

`I=(k)/(d^2)`

You change your seat to one that is eight times as far from the speakers, d' = 8d.

New sound intensity is :

`I'=(k)/(d'^2)\\\\I'=(k)/((8d)^2)\\\\I'=(1)/(64)* (k)/(d^2)\\\\I'=(1)/(64)* I`

So, the new intensity is (1/64) times of the initial sound intensity.