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The scores for math test #3 were normally distributed. If 15 students had a mean score of 74.8% and a standard deviation of 7.57, how many students scored above an 85%?

User Kazade
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1 Answer

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Answer: 1 student scored above an 85%.

Explanation:

Let X = percentage score in test (normally distributed).

Given: Sample size = 15 , mean score :
\mu= 74.8% = 0.748 ,standard deviation :
\sigma=7.57

Now, The probability that student scores above 85%:


P(X>85)=P((X-\mu)/(\sigma)>(85-74.8)/(7.57))\\\\=P(Z>1.347)\\\\=1-P(Z<1.347)\\\\=1-0.9110= 0.089

Probability that student scores above 85% = 0.089

Number of students scored above an 85% = 0.089 x 15 = 1.335 ≈ 1

hence, 1 student scored above an 85%.

User Shucao
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