Answer:
1/12
Explanation:
This type of probability is independent i.e the occurrence of one does not affect the other.
Probability = expected outcome/total outcome
For a coin:
The total sample space = {H, T} i.e 2
The probability of tossing a head will be:
P(a head) = 1/2
For a die:
Sample space S = {1, 2, 3, 4, 5, 6}
Total number of sample space n(S) = 6
If a number greater than 5 is rolled, the event outcome will be E = {6}
Pr(S>5) = n(E)/n(S)
Pr(S>5) = 1/6
The probability of tossing a head and then rolling a number greater than 5 is expressed as:
Pr(H and S>5) = Pr(H) * Pr(S>5)
Pr(H and S>5) = 1/2* 1/6
Pr(H and S>5) = 1/12
Hence the probability of tossing a head and then rolling a number greater than 5 is 1/12