Question

Kemmi Major weights 153.0 g of ammonium chloride (NH4Cl) salt. She also weighs 500.0 g of DI water. She combines the salt and the water to make her solution. Calculate the molality of the NH4Cl solution. Answer to 4 significant figures with appropriate units.

Answer 1

5.720 m

Step-by-step explanation:

Step 1: Given data

• Mass of ammonium chloride (solute): 153.0 g

• Mass of DI water (solvent): 500.0 g

Step 2: Calculate the moles of solute

The molar mass of ammonium chloride is 53.49 g/mol.

153.0 g × (1 mol/53.49 g) = 2.860 mol

Step 3: Calculate the kilograms of solvent

We will use the relationship 1 kg = 1000 g.

500.0 g × (1 kg/1000 g) = 0.5000 kg

Step 4: Calculate the molality of the solution

m = 2.860 mol / 0.5000 kg = 5.720 m