Answer:
m∈(-∞;-2]∪[6;+∞).
Explanation:
1) Δ=b²-4ac, then
m²-4(m+3)≥0; ⇔m²-4m-12≥0; ⇔ (m-6)(m+2)≥0;
2) m∈(-∝;-2]∪[6;+∝).
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