Question

There are 111 students in a nutrition class. The instructor must choose two students at random. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is
`P(k \ n \  u ) =   0.02957`

Explanation:

From the question we are told that

The total number of students is n = 111

The total number of senior nutrition major k = 19

The total number of junior nutrition major is u = 19

Generally the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random is mathematically represented as

`P(k \ n \ u ) = P(k) * P(u\ | \ k)`

Here
`P(k)` is the probability that a senior nutrition major is selected , this is mathematically represented as

=>
`P( u | k) = (19)/(111-1)`

=>
`P( u | k) = (19)/(110)`

So

`P(k \ n \  u ) =   ( 19)/(111) * (19)/(110)`

=>
`P(k \ n \  u ) =   0.02957`