Answer:
61.8 mL
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above,
Mole ratio of the acid (nA) = 1
Mole ratio of the base (nB) = 1
Next, the data obtained from the question include:
Molarity of acid, HCl (M1) = 0.341 M
Volume of base, NaOH (Vb) = 43.9 mL
Molarity of base, NaOH (Mb) = 0.480 M
Volume of acid, HCl (Va) =?
The volume of the acid needed for the reaction can be obtained as follow:
MaVa/MbVb = nA/nB
0.341 × Va / 0.480 × 43.9 = 1/1
Cross multiply
0.341 × Va × 1 = 0.480 × 43.9 × 1
0.341 × Va = 21.072
Divide both side by 0.341
Va = 21.072 /0.341
Va = 61.8 mL
Therefore, 61.8 mL of the acid, HCl is needed for the reaction.