Answer:
The confidence interval is 73 ± 4.8
Explanation:
Here, we want to construct a 99% confidence interval
Mathematically;
mean ± Z * S.D/√n
From the question
mean = 73
SD = 11.7 ounces
Z score = 2.576 for 99% Confidence interval
n = sample size = 40
Thus;
73 ± (2.576 * 11.7)/√40
73 ± 4.8
So the range of values are;
73 + 4.8 and 73-4.8
= 77.8 and 68.2
The lower boundary is 68.2
The upper boundary is 77.8