Question

In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor. hydrogen+oxygen⟶water If you burn 58.9 g of hydrogen and produce 526 g of water, how much oxygen reacted?

Answer 1

`m_(O_2)=467gO_2`

Step-by-step explanation:

Hello.

In this case, for the reaction:

`2H_2+O_2\rightarrow 2H_2O`

The correct way to compute the oxygen that reacted is by considering the mass of hydrogen, 58.9 g, its molar mass, 2.02 g/mol, the 2:1 mole ratio between hydrogen and oxygen and the atomic mass of that gaseous oxygen 32.00 g/mol; therefore we use the following stoichiometric procedure:

`m_(O_2)=58.9gH_2*(1molH_2)/(2.02gH_2)*(1molO_2)/(2molH_2) *(32.00gO_2)/(1molO_2) \\\\m_(O_2)=467gO_2`

The same result could have been obtained by using the mass of water since the law of conservation of mass is obeyed here.

Best regards!