Question

There is a temperature change of 3 °C in the room when 1.5 kg of water flows through the

radiator each second.
The specific heat capacity of water is 4200 J/kg°C.
i.
Calculate the amount of energy given to the room by the 1.5 kg of water as it passes
through the radiator.
Show your working and write down the unit.​

Answer 1

Explanation:

Q = mcT

where,

Q is heat(energy)

m is mass

c is specific heat capacity

T is change in temperature

so,

Q= 1.5kg x 4200 J/kg.C x 3C

Q = 18900J of energy

Answer 2

18900J

Step-by-step explanation:

energy = Temperature change * Mass * Specific Heat Capacity

3*1.5*4200=18900

=18900J