Solution :
• 2x²-7x +5 =0
=> 2x²-5x-2x+5 = 0
=> x ( 2x-5)-1(2x-5)=0
=> (x-1)(2x-5) = 0
• x-1=0
=> x= 1
• 2x-5=0
=> x = 5/2.
Now , Verification :
Here , a= 2 ,b= -7 and c = 5
As we know that :
• Sum of zeroes = -b/a
• 5/2+1 = -(-7)/2
• 7/2 = 7/2
LHS = RHS.
• Product of zeroes = c/a
=> 1(5/2)= 5/2
=> 5/2 = 5/2.
LHS = RHS ..
Hence, verified .
I hope it will help you.
Regards.