Answer:
1. The oxidation number of Li changes from 0 to +1
2. The oxidation number of Cu changes from +2 to 0.
3. The oxidation number of Cl remains the same in each compound.
Explanation:the equation for the reaction is given below:
Li(s) + CuCl2(s) —> LiCl(s) + Cu(s)
Next, we shall determine the oxidation number of each element in the reaction.
NOTE: 1. Oxidation number of chlorine (Cl) is always –1 in any compound because it is a ground 7 element.
Now, we shall determine the change in oxidation number of each element. This is illustrated below:
1. For Li:
Li = 0 (ground state)
LiCl = 0
Cl = –1
Li + (–1) = 0
Li – 1 = 0
Collect like terms:
Li = 0 + 1
Li = +1
The oxidation number of Li changes from 0 to +1
2. For Cu:
CuCl2 = 0
Cu + 2Cl = 0
Cl = –1
Cu + 2(–1) = 0
Cu – 2 = 0
Collect like terms
Cu = 0 + 2
Cu = +2
Cu = 0 (ground state)
The oxidation number of Cu changes from +2 to 0.
3. For Cl:
The oxidation number of Cl remains the same in each compound.
Summary:
1. The oxidation number of Li changes from 0 to +1
2. The oxidation number of Cu changes from +2 to 0.
3. The oxidation number of Cl remains the same in each compound