Question

2) The perimeter of a rectangle is 52 feet.

The length and width are represented by
two consecutive even integers. Find the
dimensions of the rectangle .

Answer 1

12 feet and 14 feet

Explanation:

Let a and b be the length and width of a rectangle

a and b are consecutive even integers

a=x, b=x+2

perimeter=52

2*(a+b)=52

2*(x+x+2)=52

2x+2=26

2x=24

x=12

a=12

b=x+2=14

Answer 2

dimensions of the rectangle are 12 ft by 14 ft

Explanation:

Let's name our unknowns :

width = x and therefore, the length according to the information given will be of size x + 2 (consecutive even integer).

Then the perimeter (addition of all four sides of the rectangle) will be the sum:

x + (x + 2) + x + (x + 2) = 52

combining like terms:

4 x + 4 = 52

subtracting 4 on both sides

4 x = 52 - 4

4 x = 48

x = 48 / 4

x = 12

so the width is 12 feet and the length must be 2 feet larger, that is: 14 feet

Then the dimensions of the rectangle are 12 ft by 14 ft.