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How many moles are in 9.01 g Be

User Efremidze
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2 Answers

1 vote

Answer:

1 mol Be

Step-by-step explanation:

First look at periodic table. Be (Beryllium) has an atomic mass of 9.012

1 mole of Be atoms = 9.012 g Be (this is your conversion factor)

Start with what you are given: 9.01 b Be. Then look at the periodic table. Be has an atomic weight of 9.012g. In order to cancel out the g place how you see here, cross out the g and your are left with mole Be on top. divide 9.01 by 9.012 to get .99977807. round that to 1 mol Be


((9.01 g Be)/(1) )((1moleBe)/(9.012 gBe) )=.99977807 moleBe

User Tony Park
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5.5k points
2 votes
5 moles is the answer
User OlegTheCat
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5.0k points