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A vertical rope is attached to an object that has a mass of 40.0 kg and is at rest.

The tension in the rope needed to give the object an upward speed of 3.50 m/s
in 0.700 s is

2 Answers

1 vote

Answer:

The answer is T=592 N

Step-by-step explanation:

Fw= 392N

a=v/t, so a=3.5ms^-1/0.7s

a=5ms^-2

Fnet=ma

T-Fw=ma

T-392N=40kg(5ms^-2)

T=592N

User CACuzcatlan
by
4.7k points
7 votes

Answer:

239.2 N

Step-by-step explanation:

Given that a vertical rope is attached to an object that has a mass of 40.0 kg and is at rest.The tension in the rope needed to give the object an upward speed of 3.50 m/s

in 0.700 s is

The tension in the rope and the weight of the mass will be acting in an opposite direction.

T - mg = ma ....... (1)

Where acceleration a = Velocity/ time

a = 3.5 / 0.7

a = 5 m/s^2

Substitutes acceleration a into the equation 1 above.

T - 40 × 9.8 = 40 × 5

T - 39.2 = 200

T = 200 + 39.2

T = 239.2N

Therefore, the tension in the rope needed to give the object an upward speed of 3.50 m/s

in 0.700 s is 239.2N

User Daniele D
by
4.3k points