Question

(?)^2-3(?)=-2 can anyone solve this

Answer 1

Answer: x = 1 or x = 2

Sub in x for ?:

x^2-3x = -2 (Move all the terms to one side, and set the equation to equal 0)

x^2-3x+2 = 0 (Factor the simple trinomial by finding two numbers that multiply to 2 and add to -3)

x^2-x-2x+2 = 0 (Factor the expression)

x(x-1)-2(x-1) = 0 (Group like terms)

(x-1)(x-2) = 0 (Solve for x by setting each term equal to 0)

x-1 = 0

x = 1

x-2 = 0

x = 2

∴ x = 1 or x = 2.