Answer:
2.31 g
Step-by-step explanation:
Step 1: Given data
- Energy added to vaporize the water (Q): 1250 cal
- Standard enthalpy of vaporization of water (ΔH°vap): 540 cal/g
Step 2: Calculate the mass of water that can be vaporized with 1250 calories of energy
We will use the following expression.
Q = ΔH°vap × m
m = Q/ΔH°vap
m = 1250 cal/(540 cal/g)
m = 2.31 g