Answer: 2/sqrt6
Explanation:
tan theta=perpendicular/base so
cot theta =base /perependicular=sqrt2/2
while sin theta=perpendicular/hypotenous=2/x
here x is unkown to find it we will use pythagoras theorem
(hypoteneous)^2=(Base)^2+(perependicular)^2
=(sqrt 2)^2+(2)^2
=2+4
(hypoteneous)^2=6
hypotenous =sqrt6
so
sin theta=2/sqrt6