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A student walks from her car to a tree, 29 meters away at 1 m/s, and returns at 6 m/s. What is her average speed for the entire trip in m/s?

A student walks from her car to a tree, 29 meters away at 1 m/s, and returns at 6 m/s. What is her average speed for the entire trip in m/s?
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A student walks from her car to a tree, 29 meters away at 1 m/s, and returns at 6 m/s. What is her average speed for the entire trip in m/s?

User Andyhasit
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8.4k points

1 Answer

3 votes
The entire trip is 2x29 = 58 m.
The time taken there = 29 s.
On the wY back it takes 29/6 = 4.8 s
Total time taken .= 33.8 s
Average speed = 58/33.8= 1.7 m/s
User Dan Udey
by
8.1k points
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