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A 5 Kg mass has an initial speed of 5m/s. After 3 sec, it has come to a speed of 70 m/s.

a. What is the acceleration of the mass?
b. What net force is acting on the mass during those 3 seconds?

User Jaustin
by
7.2k points

1 Answer

4 votes

Answer:

a


a = 21.7 \ m/s^2

b


F = 108.5 \ N

Step-by-step explanation:

From the question we told that

The mass is m = 5 kg

The initial speed
u = 5 m/s

The time taken to attain
v = 70 \ m/s is t = 3 s

Generally from kinematic equation we have that


v = u + at

=>
70 = 5 + a * 3

=>
a = 21.7 \ m/s^2

Generally the force acting is mathematically represented


F = m * a

=>
F = 5 * 21.7

=>
F = 108.5 \ N

User Topanga
by
8.2k points