Find the equation of a parabola with a focus at (–2,–3) and a directrix at y = –5. A) y = 1∕4(x – 2)2 – 4 B) y = –1∕16(x + 2)2 – 4 C) y = 1∕4(x + 2)2 – 8 D) y = 1∕4(x + 2)2

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Find the equation of a parabola with a focus at (–2,–3) and a directrix at y = –5. A) y = 1∕4(x – 2)2 – 4 B) y = –1∕16(x + 2)2 – 4 C) y = 1∕4(x + 2)2 – 8 D) y = 1∕4(x + 2)2 – 4

asked Dec 20, 2021 79.6k views

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Find the equation of a parabola with a focus at (–2,–3) and a directrix at y = –5.

A)

y = 1∕4(x – 2)2 – 4

B)

y = –1∕16(x + 2)2 – 4

C)

y = 1∕4(x + 2)2 – 8

D)

y = 1∕4(x + 2)2 – 4

Mathematics
college

BrunoMartinsPro asked

by BrunoMartinsPro

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2 Answers

1 vote

Answer:

It"s (C) byeeee and ur welcome

RDavey answered Dec 22, 2021

by RDavey

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3 votes

C if i’m not mistaken

Keenora Fluffball answered Dec 26, 2021

by Keenora Fluffball

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