Question

Write an equation of the line passing through the point (8,-5) that is parallel to the line 2x – 6y=-3.

y = mx + b

Answer 1

y=
`(1)/(3)\\`x -
`(23)/(3)`

Explanation:

Ist put the first equation in y=mx+b form

2x-6y=-3

subtract 2x on both sides

2x-6y=-3

-2x =-2x

-6y=-2x-3

then divide both sides by -6

-6y=-2x-3

-6

that gives y=
`(1)/(3)`x+
`(1)/(2)` for the original equation

Then plug in the point and slope in y=mx+b

Use the same slope since the lines are parallel

(-5)=(
`(1)/(3)`)(8)+b

-5=
`(8)/(3)`+b

then subtract 8/3 on both sides and that gives

-23/3 = b

then you can make the new equation using -23/3 for you b and 1/3 for your slop m