Answer:
Please find the answer in the explanation
Explanation:
Given that a red ball rolls for 6 meters across a sticky level surface and slows down to a stop. the ball was rolling at 36 meters per second when it began to roll across the sticky surface. To find the acceleration, let us use third equation of motion
V^2 = U^2 + 2as
As the object is moving to stop, V = 0
0 = U^2 - 2as
36^2 = 2 × a × 6
1296 = 12a
a = 1296 / 12
a = 108 m/s
The velocity final = 0
The velocity initial = 36 m/s
the velocity average = (36 + 0)/2
Average velocity = 36/2 = 18m/s
the distance the ball rolled = 6m
and the time of the balls roll across the sticky surface will be achieved by using first equation of motion
V = U + at
V = 0
0 = 36 - 108t
108t = 36
t = 36 / 108
t = 0.3 seconds